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Fraction with Zero question

Name: Anonymous 2007-07-01 14:40 ID:35VwoViQ

This is for the *genuises*. when posed with the problem, "what is the answer to 0/0?" i have come across three different solutions and im not sure which is correct:

1. since any fraction with 0 as the denominator cannot be solved, then the answer is "undefined"

2. since any fraction with 0 as the numerator is zero, then the answer is "zero"

3. finally, since any fraction in which the denominator and the numerator have the same numerical value is equal to one, the answer must be "one"


so which one is correct?

Name: Anonymous 2007-07-01 15:09 ID:xugRnLct

Answer is DNE, now GTFO

Name: Anonymous 2007-07-01 15:13 ID:fxhdLsot

>>1
Depends on the context. The answer can be 9000 if I want it to. L'Hopital's innit.

Name: Anonymous 2007-07-01 15:45 ID:5BWgas6f

>>2
So, if I have an equation that can be simplified to:

x = 1 - DNE

what would be the answer?

Name: Anonymous 2007-07-01 17:36 ID:35VwoViQ

>>2

 what is DNE

Name: Anonymous 2007-07-01 18:15 ID:fKB9CXYB

NULLITY

Name: Anonymous 2007-07-01 18:27 ID:sxb7XUN3

>>1
That's the very reason the operation is undefined. It does not have well-defined value.

Name: Anonymous 2007-07-01 18:49 ID:5BWgas6f

Is DNE the same as NaN and INF?

Name: Anonymous 2007-07-01 20:03 ID:fKB9CXYB

>>8

No. NaN and +/- INF are engineering terms for certain computer functions called for values outside of their [normal] domain.

Name: Anonymous 2007-07-01 22:03 ID:MgajGKCC

DNE means "Does Not Exist"

Although, technically I think 0/0 is just called "indeterminate form, zero over zero".

Name: 4tran 2007-07-01 22:04 ID:RkVGe6xf

DNE = Does Not Exist

It's not quite NaN, but it's somewhat related.

Name: Anonymous 2007-07-02 8:44 ID:rENUD2tF

What's the difference between DNE and NaN then? Like how many NaNs make up for a DNE?

Name: Anonymous 2007-07-02 11:01 ID:TXGWzDpB

>>12

Like 9 said, but slightly differently:
DNE is shorthand for a logical statement, "the set of solutions is empty", or "the solution does not exist".
NaN and +-INF are machine specifications for values that fall outside the range of finite machine numbers. They are placeholders used so that the variable containing the solution to an equation can be specified to exist, without actually having a (finite) numerical value.

Name: Anonymous 2007-07-02 11:49 ID:4qU0o9aZ

>>13


That seems weird. The set of solution is infinite. 0/0 can be any value you want, as a limit process anyway.

Name: Anonymous 2007-07-02 13:18 ID:dvs94/Cz

>>14

Limits where both numerator and denominator approach zero _can_ have any complex value (depending on the limit) or be undefined, but the "fraction" 0/0 just doesn't make any sense because zero doesn't have a multiplicative inverse (you might as well ask "What's the numerical value of zero divided by true love?").

Name: Anonymous 2007-07-02 14:21 ID:Gv6LkwUy

>>13
So DNE is pretty much like Ø, and it can be said that 0/0 = Ø?

Name: Anonymous 2007-07-02 17:27 ID:p+paQ/iJ

the answer is undefined, or DNE, division by 0 supercedes a numeratot of 0.

Name: Anonymous 2007-07-02 17:29 ID:KCoqNVgZ

if x/0 = inf than inf * 0 = x ? This means inf * 0 = all posotive rela numbers? Wrong. It is not an inequality and remainds undefined

Name: YouAllSuck 2007-07-02 17:56 ID:Heaven

>>10
>>3

Niggers, that is for when you are taking a limit and the limit becomes 0/0 (same with l'hopital's rule).  As for the expression 0/0 or inf/inf, it simply does not exist.  Now go kill yourselves.

Name: CSharp !FFI4Mmahuk 2007-07-03 1:27 ID:R3bEp1GV

>>16
No, they're... They're doing it wrong.
0/0 is undefined, and is part of a group of indeterminate forms (such as 0^0, inf/inf, etc.). 0/0 does not equal DNE. DNE is what you get as the result of taking a limit that doesn't actually exist.
Example:
The limit of 1/x as x approaches 0. Looking at the graph of 1/x, you can see that coming from the left, 1/x approaches -inf. Coming from the right, it approaches inf. Because there is a disparity where the two meet (i.e. it is both infinity and negative infinity), the limit is said not to exist.
You can't use NaN or DNE in any sort of equation; they're just what you get when you've screwed up somewhere.

Name: imsmart 2007-07-03 14:38 ID:p5rC80/r

I asked smarterchild what 0/0 was and he said NAN

Name: Anonymous 2007-07-03 14:49 ID:rL+vglbp

So 0 * NaN = 0?

Name: Anonymous 2007-07-03 15:00 ID:k66j5WEp

>>16

No. Ø is defined (by the ZF axioms).

Name: Anonymous 2007-07-03 15:02 ID:p5rC80/r

no the number 0/0 is not a real number. Let's go back to basic math.

Numerator: How much out of a piece of something or part there is.

Denominator: How many parts of a peice of something there are.

Now using those definitions for the fraction 0/0, lets define the fraction. The denominator is 0. That means there is 0 parts to nothing. It isn't going on for infinite, there are no parts to it for it to go on for infinite. Now for the numerator, the numerator divides out of the denominator as we all know from the definitions (remember, it is how many parts out of the whole, and the denominator is how many parts there are). So, if there aren't any parts, then there is no numerator. So this fraction is non-existant. That is why this is not a real number.

Now you are going to ask, what does it equal? Well, if it's not a real number, nothing! hahaha, non-real numbers don't equal anything because they are either errors in equations or things like infinite or etc. So, I hope this ends this <_<

Name: Anonymous 2007-07-03 15:26 ID:5l7f+9pj

has anyone ever heard of the box analogy to describe divide by zero operations? i think its very good way to 'visualize' why you can't divide by zero.

Name: Anonymous 2007-07-03 16:52 ID:k66j5WEp

>>24

That's an intuitive approach. An algebraic approach is clearer. The additive identity doesn't have a multiplicative inverser.

Name: 4tran 2007-07-04 0:37 ID:Heaven

>>24
I have difficulty understanding your reasoning.  In any case, it is not true that "non real numbers don't equal anything".  i is not real, and is very well defined.  0/0 is not well defined.

>>26
win

Name: Anonymous 2007-07-04 15:15 ID:fKgOLnsu

>>20

"0/0 is undefined, and is part of a group of indeterminate forms (such as 0^0, inf/inf, etc.)"

Congratulations. There are 27 posts on this thread, and you're all fucking morons.

x/0 for x != 0, is undefined.
0/0 is indeterminate, NOT undefined.

indeterminate != undefined.

l2/math/ before you fucking post shit to do with it.

Name: Anonymous 2007-07-07 19:37 ID:8gmw+U/F

It is indeterminant.

Name: Anonymous 2009-03-18 3:12

I feel the need, the need for weed!

Marijuana MUST be legalized.

Name: Anonymous 2010-10-07 10:35

According to Euler: 1/0 may be undefined but 2/0 is twice that number. But he was a little crazy.
According to Hardy: any number divided by 0 is meaningless.

But really, we all know that the expression 1/0 is really meaningless, but the right hand limit of 1/x as x -> 0 = infinity. There is no argument here (I hope). Can we now agree that 0/0 is the same as 0 * (1/0) which is meaningless? Or can we write 0/0 in a way which is meaningful, or can we write it in a different way which allows us to make some sort of conclusion about what it's meaning is?

Name: Anonymous 2010-10-07 10:38

Or one can just point out the fact that division by zero is not allowed in the field of real numbers, and we can just leave it as that. So (any real / 0) is undefined in the field of real numbers.

Name: gasman 2010-10-07 14:24

Your 3rd assertion is incorrect -- it must exclude fractions whose denominator is zero, i.e., 0/0. This is because of your 1st statement: Division by zero (including a fraction whose denominator equals zero) is undefined for real numbers and most other number domains.

The "fraction" 0/0 is therefore undefined and as such has no value. However there exist limits of the form x/x where x approaches zero. The form is said to be indeterminate and it's corresponding limit may exist and have any of various values, depending on the original expression.

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