1^-1 + 2^-1 + 3^-1 + 4^-1 + 5^-1 + ... N^-1 = Y
Can anyone simplify this please.
Name:
Anonymous2007-06-26 5:10 ID:xRFYRwGE
In other words I want to sum
1/floor(x)
over a range.
Name:
Anonymous2007-06-26 8:53 ID:dkFHt3Hu
"Anonymous not great at maths"
I am still confused that anonymous can be amazing one minute, but very bad the next. Sometimes it seems like (s)he has multiple personalities.
Name:
Anonymous2007-06-26 9:21 ID:xRFYRwGE
Anonymous is sometimes great at math - prove it to meh!
btw I tried the intergral ln(x) of 1/x but this isn't accurate because 1/x is countinous not discrete like I showed in >>1 (I think).