vector calculus question

I have an exercise where I have to find the double integral over S of (x dy ^ dz), where the surface S is defined by the parametric funcion r(u,v) = (ucosv, usinv, v) with u belonging to [0,1] and v belonging [0,2pi]. Usually I could easily do this but the notation dy ^ dz is really confusing me, because it's the first time I've seen it and I don't know what it means... blame me not going to classes. well, can any of you help me? thanks

also, if someone has a good site with vector calculus topics I'd very much appreciate it. thanks.

Is it the wedge product(^) that's confusing you?

I have no idea if the caret here is meaning the wedge product. If it does, please explain of what the wedge product means and what it means between the differentials.

Generally, in vector calculus at this level, writing the wedge product out for every multiple integral is superfluous. So, unless you are supposed to know what it means, pretend it isn't there.

So, SS x dy dz   (where the S is an integral sign), over surface S, defined by r(u, v) = (ucosv, usinv, v).

Unless that x is supposed to be part of a vector, this looks like a change of variables problem, probably polar or cylindrical.

it most probably means dy/dx

>>5
No, it doesn't. It's a generalized version of the cross product.

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