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omg new proof

Name: .999...9 =/= 1 2007-05-12 6:26 ID:/qcJW6wi

Assumptions
If A = B, then
a)  A-B = 0
b) A = (A+B)/2 = B

If A > B, then
a)  A-B > 0
b) A > (A+B)/2 > B


Let A = 1, B = .999...9
a) A-B = 1-.999...9 = .000...1 =/= 0
b) (A+B)/2 = (1+.999...9)/2 = 1.999...9/2 = 1.999...95 < A

Therefore, .999...9 =/= 1

Name: Anonymous 2007-05-17 12:49 ID:Heaven

>>92
It isn't constructivism. Constructivists are at least smart enough to realize that redefining the real numbers to be the rational numbers is pointless, and mainly focus on arguing that we shouldn't use the real numbers.

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