omg new proof

Assumptions
If A = B, then
a)  A-B = 0
b) A = (A+B)/2 = B

If A > B, then
a)  A-B > 0
b) A > (A+B)/2 > B


Let A = 1, B = .999...9
a) A-B = 1-.999...9 = .000...1 =/= 0
b) (A+B)/2 = (1+.999...9)/2 = 1.999...9/2 = 1.999...95 < A

Therefore, .999...9 =/= 1

>>79
fi·nite – adjective
1. having bounds or limits; not infinite; measurable.  [yes]
2. Mathematics. a. (of a set of elements) capable of being completely counted.  [unrelated]
b. not infinite or infinitesimal.  [yes]
c. not zero.  [yes]

Based on the Random House Unabridged Dictionary, © Random House, Inc. 2006.
(abridged, courtesy of dictionary.com)

My argument is not an assertion about real numbers.  My argument claims that .999... is a finite number.  By the first definition, I placed a definite bound on the number.  It is most definitely not infinite.  I don't care if you believe it's a real number.  The damn thing is finite.