omg new proof

Assumptions
If A = B, then
a)  A-B = 0
b) A = (A+B)/2 = B

If A > B, then
a)  A-B > 0
b) A > (A+B)/2 > B


Let A = 1, B = .999...9
a) A-B = 1-.999...9 = .000...1 =/= 0
b) (A+B)/2 = (1+.999...9)/2 = 1.999...9/2 = 1.999...95 < A

Therefore, .999...9 =/= 1

>>38
Wrong again.

0.9... is NOT a number. Sure, 0.9 is a real number, so is 0.99, 0.999, etc; but no matter the number of 9s there are in the number you pick, at least one will always be missing. An element that is not in R cannot equal an element that is in R.

So drill it into your stupid fucking head: The real numbers are an infinite set of FINITE numbers; not an set infinite set of infinite numbers.