omg new proof

Assumptions
If A = B, then
a)  A-B = 0
b) A = (A+B)/2 = B

If A > B, then
a)  A-B > 0
b) A > (A+B)/2 > B


Let A = 1, B = .999...9
a) A-B = 1-.999...9 = .000...1 =/= 0
b) (A+B)/2 = (1+.999...9)/2 = 1.999...9/2 = 1.999...95 < A

Therefore, .999...9 =/= 1

>>26
"sum(n=1, +inf)[(9)10^-n] != 1"
M-M-M-Monster fail!

Here's an idea: Take a fucking high school calculus class so that you understand why you're wrong in this statement. Then, take a fucking analysis class so that you understand the definition of the real numbers. When you accomplish these two things - and it'll take you a while, since you seem pretty slow - you can come here and discuss whether or not 0.999.. = 1. But of course, if you've actually accomplished these two things, then you won't believe that 0.999... != 1, so it's a bit of a catch 22. (Catch 21.999... lolol)