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omg new proof

Name: .999...9 =/= 1 2007-05-12 6:26 ID:/qcJW6wi

Assumptions
If A = B, then
a)  A-B = 0
b) A = (A+B)/2 = B

If A > B, then
a)  A-B > 0
b) A > (A+B)/2 > B


Let A = 1, B = .999...9
a) A-B = 1-.999...9 = .000...1 =/= 0
b) (A+B)/2 = (1+.999...9)/2 = 1.999...9/2 = 1.999...95 < A

Therefore, .999...9 =/= 1

Name: Anonymous 2007-05-19 12:29 ID:jqaiHHIB

No it doesnt, but thats quite irrelevant. The point is that the mathematical model, even if it is only probability, cannot go farther than one atom and still express something other than the probability of that atom decaying. If there was an indivisible level of reality, it logically follows that it would be the end of all irrational numbers, and the farthest a .9999... can go.

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