Name: dev0 2007-05-03 3:00 ID:fAyRmi7E
what can u tell about vectors?
A . B = |A||B|cos theta
i.i = j.j = k.k = 1
i.j = j.k = k.i = 0
A = i*x1 + j*y1 + k*z1
B = i*x2 + j*y2 + k*z2
A.B = (i*x1 + j*y1 + k*z1).(i*x2 + j*y2 + k*z2)
= (i*x1 + j*y1 + k*z1).(i*x2)
+ (i*x1 + j*y1 + k*z1).(j*y2)
+ (i*x1 + j*y1 + k*z1).(k*z2)
= (i*x1).(i*x2) + (j*y1).(i*x2) + (k*z1).(i*x2)
+ (i*x1).(j*y2) + (j*y1).(j*y2) + (k*z1).(j*y2)
+ (i*x1).(k*z2) + (j*y1).(k*z2) + (k*z1).(k*z2)
= (i.i)*x1*x2 + (j.i)*y1*x2 + (k.i)*z1*x2
+ (i.j)*x1*y2 + (j.j)*y1*y2 + (k.j)*z1*y2
+ (i.k)*x1*z2 + (j.k)*y1*z2 + (k.k)*z1*z2
= (1)*x1*x2 + (0)*y1*x2 + (0)*z1*x2
+ (0)*x1*y2 + (1)*y1*y2 + (0)*z1*y2
+ (0)*x1*z2 + (0)*y1*z2 + (1)*z1*z2
= x1*x2 + y1*y2 + z1*z2
AxB = |A||B|sin(theta)n
= (i*x1 + j*y1 + k*z1)×(i*x2 + j*y2 + k*z2)
x| i j k
----------
i| 0 k -j
j|-k 0 i
k| j -i 0
A×B = (i*×1 + j*y1 + k*z1)×(i*×2 + j*y2 + k*z2)
= (i*×1 + j*y1 + k*z1)×(i*×2)
+ (i*×1 + j*y1 + k*z1)×(j*y2)
+ (i*×1 + j*y1 + k*z1)×(k*z2)
= (i*×1 + j*y1 + k*z1)×(i*×2)
+ (i*×1 + j*y1 + k*z1)×(j*y2)
+ (i*×1 + j*y1 + k*z1)×(k*z2)
= (i*×1)×(i*×2) + (j*y1)×(i*×2) + (k*z1)×(i*×2)
+ (i*×1)×(j*y2) + (j*y1)×(j*y2) + (k*z1)×(j*y2)
+ (i*×1)×(j*z2) + (j*y1)×(k*z2) + (k*z1)×(k*z2)
= 0*×1*×2 + -k*y1*×2 + j*z1*×2
+ k*×1*y2 + 0*y1*y2 + -i*z1*y2
+ -j*×1*z2 + i*y1*z2 + 0*z1*z2
= i*(y1*z2-z1*y2) + j*(×1*y2-y1*×2) + k*(×1*y2-y1*×2)
/x1 y1 z1\
|x2 y2 z2|
\ i j k/