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Integrals

Name: Anonymous 2007-04-18 18:57 ID:3jbqiejJ

So explain me this, I have never studied integrals and suddenly im faced with them while calculating work of electric fields.

why does a S(0,1 to infinity ) of 1/(4.Pi.E0.((15.10^6)/r^2).er.dr

equals (15.10^6)/(4.Pi.E0 ?
specifically, how do integrals work?

Name: Anonymous 2007-04-18 19:26 ID:isF8kggk

http://www.mathematicshelpcentral.com/lecture_notes/calculus_2_folder/introduction_to_integral_calculus.htm

Also, write your integral more clearly. I can't make heads or tails of it.

Name: Anonymous 2007-04-18 19:36 ID:3jbqiejJ

S ( 0,1 to infinity ) dr/r^2
removed the constants.

Name: Anonymous 2007-04-18 20:08 ID:Qj7iUiX2

Integration is effectively the opposite of differentiation.
So Sar^n dr = a/(n+1)r^n+1 (plus constant) because, if you differentiate that, you get ar^n. The constant is known as the constant of integration; it's arbitrary because it disappears if you differentiate it.

In your case, a is the constant you removed, and n=-2.

Name: Anonymous 2007-04-19 2:24 ID:Heaven

Why are you calculating work if you haven't taken calculus?

Math first, physics second.

Name: Anonymous 2007-04-19 6:12 ID:Vrj1dRK6

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Name: Anonymous 2007-04-19 12:05 ID:HgHOjW8Y

You can also think of definite integrals as area under a curve

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