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Primitives

Name: Anonymous 2007-01-18 20:51

i just don't know how to primitivize very well

what should i do when i need to primitivize a fraction

could you please explain me clearly how this function was primitivized?
http://img369.imageshack.us/img369/1093/zzzls4.jpg

Name: Anonymous 2007-01-18 22:31 (sage)

It's a black art.

Name: Anonymous 2007-01-18 22:47

opposite of differentiation

Name: Anonymous 2007-01-19 4:17

let t = tan(x), dt = sec^2(x)dx, 1+t^2 = sec^2(x)

the integral becomes: I[sin(x)dx/cos^2(x)]

let u = cos(x)... etc

the integral then becomes u^-1 => I = sec(x)

from above you have

t = tan(x)
=> cos(x) = (1+t^2)^-(1/2)
=> sec(x) = (1+t^2)^(1/2), as required

Name: Anonymous 2007-01-19 4:25

>>4 here

how embarassing, I just realized there's a much simpler way to solve this integral without using trig substitutions. simply let u = 1+t^2, substitute in du and u, and the result follows. :p

Name: Anonymous 2007-01-19 9:12

wtf are primitives and primitivize?

Name: Anonymous 2007-01-19 11:40 (sage)

>>6
In calculus, an antiderivative, primitive or indefinite integral of a function f is a function F whose derivative is equal to f, i.e., F′ = f. The process of solving for antiderivatives is antidifferentiation (or indefinite integration). They are also called integrals, but this usage is not universally accepted. Antiderivatives are related to definite integrals through the fundamental theorem of calculus, and provide a convenient means for calculating the integrals of many functions.

Name: Anonymous 2007-01-19 12:44

>>7
What kind of third world country uses the term primitives anyway.

Name: Anonymous 2007-01-19 13:49

>>8

Ba-dum tch

Name: Anonymous 2007-01-19 16:51

um...i'm only allowed to primitivize it using these (http://www.math.ist.utl.pt/~amoura/AMII/Primitivas.pdf)

Name: Anonymous 2007-01-19 17:30

>>10
Your people spelled sin, sinh, cosh, etc. incorrectly.

Also, you're a dumbass. It's the fucking antiderivative; if you aren't mentally capable of handling this easily, you shouldn't be in any career that requires it.

Name: Anonymous 2007-01-19 17:43

>>11
Actually it isn't spelled incorrectly, it's in portuguese. You could have scrolled down to see that the text is in English.
Secondly, thanks for the diss, it really helps a lot.

Name: Anonymous 2007-01-19 17:46

I was able to figure it out with the formula P(u'u^a)=(u^(a+1))/(a+1)

Name: Anonymous 2007-01-19 18:02

>>12
Admittedly, I haven't much right to demand to have my intelligence respected while trolling.

I'm betting you're not the OP, though. Thanks for the acknowledgement of my dis; it doubles the helps.

Name: Anonymous 2007-01-19 23:19

oops! this isnt furry

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