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.9999999... = 1

Name: Anonymous 2006-12-26 2:23

1/3 = .3333...
2/3 = .6666...
3/3 = 1 = .9999

Name: Anonymous 2007-01-02 3:08

>>39
Yes you do.

Divide 3 by 3. 3/3 is multiplicatively expressed as 3*3^-1.

3^-1 = .33333..
3    =  3
Multiply .3333 by 3, and you end up with, drumroll please, .999..

Name: Anonymous 2007-01-02 3:56

>>38
1/1 = 1/0? Fucking retard.

Name: Anonymous 2007-01-02 13:32

>>39
Yes, you will, because 0.999... = 1.

Name: Anonymous 2007-01-02 17:25

>>39
Read what I typed.  You are just talking in circles.
>>41
That sucked.  I said divide, not convert division into other operations.

Name: Anonymous 2007-01-02 17:27

>>43 which referenced >>39 (correction to >>44 above)
Read what I typed.  You are just talking in circles.

Name: Anonymous 2007-01-02 18:21

>>41
Also, that manoeuvre doesn't even work with most cases: 1/1, 2/2, 4/4, etc. unless you pull another fast one and convert them to 3/3 first.  And, you trade one problem for another, relying upon another infinite set version of a fraction (1/3 = .333..., a representation that I poo-poo on) upon which you attempt to perfom an arithmetic operation upon (multiply by 3), which I also poo-poo on.

But that just makes more points to argue about.  All I wanted was in that post was division performed, eg 4 divided by 4.

Name: Anonymous 2007-01-02 18:23

>>45
Proving that 0.999... = 1 is simple, since 0.999... = lim n->+inf of the sum from i=1 to n of (0.9 * 10^(-i)), which is equal to 1. Hence 1/1 = 2/2 = 4/4 = 1 = 0.999...

Name: Anonymous 2007-01-02 18:27

That's just repeating what you said.  You are talking about your proofs when something else was asked to be demonstrated.

Name: Anonymous 2007-01-02 18:51

Sure, you might be able to prove that .999... = 1, but how do you prove that .999 equals the experience that a black man living in America must go through?

Name: Anonymous 2007-01-02 20:28

1/3!=.33333...
It's just as close as we can get, the end.

Name: Anonymous 2007-01-02 20:37

>>48
>>50
Willful ignorance has no place in math. gb2/pol/.

Name: Anonymous 2007-01-02 23:05

>>51
gb2 /trol/

Name: Anonymous 2007-01-03 2:19

>>52
Listen very carefully: I proved that 0.999... = 1. Hence, 1/1 = 2/2 = 4/4 = 1 (you agree with this, right?) which, in turn, = 0.999...

Name: Anonymous 2007-01-03 2:35

>>53
Uh, that's not what I asked for.  I didn't ask for a proof, I asked for a calculation.

Name: Anonymous 2007-01-03 2:37

specifically, using the operation division.

Name: Anonymous 2007-01-03 2:40

>>54
You don't have the slightest fucking clue what you're talking about. Calculations are components of proofs and, in math, proofs trump all. Disprove him or concede.

Name: LordRiordan 2007-01-03 12:10

If .9999... were = 1 then it would look like 1 instead of .9999

Name: Anonymous 2007-01-03 15:20

>>56
No U, I didn't ask for a proof in my much earlier post.  You are talking around what I was asking for, as if you believe that I am talking about what you want to talk about.  Read the thread.  I'm not talking about 0.999.... = 1 and making proofs one way or the other, that's some other guy.  I wanted a demonstration that 0.999... can actually arise from the operation of division in the first place, as in 4/4.  I can only conclude that you don't understand, or can't do it and are ashamed to say it, or are too hung up on proving 0.999... = 1 in every damn reply regardless.

Name: Anonymous 2007-01-03 17:10

>>58

and you seem to not understand that 4/4=1=.999...

Name: Anonymous 2007-01-03 21:08

>>58
0.999... can arise from the operation of division because it is equal to 1, and 1 arises from the operation of division. If you still can't follow this, gb2/middleschool/.

Name: Anonymous 2007-01-04 1:53

you can get it by writing out the long division for 1 divided by 1, and purposely leaving a remainder, lolz.
    0.999...
1|¯ 1.000
   -0
    10
    -9
     10
     -9
      10

Name: Anonymous 2007-01-04 3:45

>>58
If you understood that .999... = 1, you wouldn't be asking that question. Does 1/4 = .24999... | 4/4 = .999... make it any easier?

Name: Anonymous 2007-01-06 0:38

>>61
Yes, that's my point.  You can only get it with fucking up a long division.  0.9999... is a fucked up way to represent 1.
>>62
I ask the question to reveal the lack of appearance of 0.999... unless it is specially contrived.  I know that if you defined 0.999... as a limit you get 1, but really so what?

Name: Anonymous 2007-01-06 1:31

>>63

if .999... was not the same as 1, a lot of shit wouldn't work. calculus depends on this being true, and i'm sure it goes even deeper than that. that's "so what".

Name: Anonymous 2007-01-06 1:56

>>64
damn son, that's pretty deep

Name: Anonymous 2007-01-06 2:05

>>63
"if you defined 0.999... as a limit"

Protip: All real numbers are defined as limits.

Name: Anonymous 2007-01-06 5:24

"..." DOESN'T REPRESENT A LIMIT, IT REPRESENTS A PROCESS, MORONS!!

Name: Anonymous 2007-01-06 5:34

>>67
See >>66.
What kind of process is .25000...?

Name: Anonymous 2007-01-06 14:45

>>67

yeah, like the way 1 doesn't really equal to one, it equals to .5+.25+.125... i mean 1 gets really really close to 1 but 1 never equals 1.

Name: Anonymous 2007-01-06 15:06

>>69
This is magnificent proof that 0.99999... != 1.

Name: Anonymous 2007-01-06 15:25

Bullshit. Here's proof that 0.99999 = 1:

>>> j=0
>>> for i in xrange(1,100):
...  j += 2**-i
...  print j,
...
0.5 0.75 0.875 0.9375 0.96875 0.984375 0.9921875 0.99609375 0.998046875 0.9990234375 0.99951171875 0.99975585937
5 0.999877929688 0.999938964844 0.999969482422 0.999984741211 0.999992370605 0.999996185303 0.999998092651 0.999
999046326 0.999999523163 0.999999761581 0.999999880791 0.999999940395 0.999999970198 0.999999985099 0.9999999925
49 0.999999996275 0.999999998137 0.999999999069 0.999999999534 0.999999999767 0.999999999884 0.999999999942 0.99
9999999971 0.999999999985 0.999999999993 0.999999999996 0.999999999998 0.999999999999 1.0 1.0 1.0 1.0 1.0 1.0 1.
0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.
0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

Name: Anonymous 2007-01-08 16:26

>>64
Calculus doesn't give a shit about the representation 0.999... specifically.  A number and the representation of the number are not the same thing.  We define the representations the way we do by convention.  (Yes, your convention is the accepted convention.)  The way we define the underlying number concept is another thing.
>>66
Again, tease apart the concept of number from the concept of the representation of a number.
>>67
obvious unfunny troll

It is worth noting that many typical text books (and Mathworld for easy-to-find online source) define series and their related sums not quite the same way as other sources (see Wikipedia for easy-to-find online source).  I don't want to argue about one way being "the truth" as there is nothing new to add to what has been argued already -- what I want to say is that it is no surprise that people argue over what is meant by 0.999... when there are these two different common descriptions of series and their sums.  If you want to be more convincing in your argument, you need to keep in mind how many people may have been taught, and speak to that (next post):

Name: Anonymous 2007-01-08 16:29

Mathworld - Convergent:
Most commonly, it is used to describe a convergent sequence or convergent series, where it essentially means that the respective series or sequence approaches some limit (D'Angelo and West 2000, p. 259).

Mathword - Convergent Series:
A series is said to be convergent if it approaches some limit (D'Angelo and West 2000, p. 259).  Formally, the infinite series is convergent if the sequence of partial sums is convergent.

Mathworld - Series:
A series is an infinite ordered set of terms combined together by the addition operator.
If the sequence of partial sums converges to a definite value, the series is said to converge.

The above definitions suggest that to converge means to approach a limiting value, and so that a series sum approaches a limiting value.

Wikipedia - Series (mathematics):
The sum of an infinite series is the limit of the sequence of partial sums.
This limit can have a finite value; if it does, the series is said to converge.

The above defintion states that to converge means to become equal to the limiting value, so that the series sum is that limiting value.

The Mathworld and Wikipedia definitions conflict in thier treatment of the infinite series.  Mathworld treats the convergent series as a sum that is approaching the limit, while Wikipedia defines a sum of the convergent series as that limit. (Yes, elsewhere on Mathworld you may find definitions of real numbers that use the limit.)

People argue with you over 0.999... because they believe they see a series sum that approaches a limit, which may have been how they were taught about series sums.  This idea is reinforced by their memory of learning long division, where they produce each digit successively from left to right, suggesting in their minds a successiveness to the parts rather than an immediate complete whole that has been partitioned into infinitely many parts.

Name: Anonymous 2007-01-09 2:48

Hm. After a few months of being away, I decided to come check out how /sci/ has been.

Yep. Still sucks.

Name: Anonymous 2008-09-08 6:36

big cock

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