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Division by 3 does not exist

Name: LordRiordan 2006-11-26 21:40

Think about it... how can you have 3 equal parts of an object? The decimate representation is impossible and one side always has to be bigger then the other. This is also why there is no such thing as 360 equal degrees in a circle as one degree has to be off by a little bit... There are no 360 numbers that will add up to 1 whole object either.

Name: LordRiordan 2007-01-20 15:02

274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT 274 IS A FUCKING FAGGOT

Name: Anonymous 2007-01-21 13:44 (sage)

THREAD CLOSED - Stop bumping this thread LordRiordan, you fat shut-in faggot.

Name: Anonymous 2007-01-21 13:45 (sage)

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Name: Anonymous 2007-01-21 13:45 (sage)

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Name: Anonymous 2007-01-21 13:45 (sage)

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Name: Anonymous 2007-01-21 13:45 (sage)

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Name: Anonymous 2007-01-21 13:45 (sage)

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Name: Anonymous 2007-01-21 16:43

mn

Name: Anonymous 2007-01-21 20:08 (sage)

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Name: Anonymous 2007-01-21 20:08 (sage)

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Name: Anonymous 2007-01-21 20:08 (sage)

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Name: Anonymous 2007-01-21 20:08 (sage)

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Name: Anonymous 2007-01-21 20:10 (sage)

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Name: LordRiordan 2007-01-21 22:57

*sigh* 293 is a faggot.

The fact remains that .999... isn't = to 1. That defeats [0,1)

Name: Anonymous 2007-01-21 23:02

>>294
Excellent tactic: declare your position fact and present no argument.

Note that [0,1) doesn't include .999..., since an open set requires that you be able to move closer no matter how close you get and, even if .999... and 1 were different numbers, there could be no numbers between them.

Name: LordRiordan 2007-01-21 23:15

[0,1) includes all numbers including 0 and up to 1 but not including 1. This would include .999...? What's wrong with not being able to be any numbers between .999... and 1?

Name: Anonymous 2007-01-22 0:17

An open set by definition has no single 'last number' - that is a closed set. [0,1). If you pick any positive number x less than 1, it will be in that set, and there will be infinitely many numbers y s.t. x < y < 1. This is what it means for a set (in this case, the reals) to be dense.

To tie this back to the topic, 1 is by definition the smallest number greater than all numbers in the set [0,1). Therefore, any number that is greater than all numbers in that set must be >= 1. .999... is obviously not greater than 1, so it is equal. QED. Stop being religiously devoted to your position and just let go for a sec. No one is going to think less of you for slowing down and re-examining your ideas.

Name: Anonymous 2007-01-22 0:38 (sage)

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Name: Anonymous 2007-01-22 0:59

>>302
Well, I'm willing to try to reason with him.

Name: LordRiordan 2007-01-22 2:42

Im sad I didn't 300 get. I agree with anon 303.

Name: Anonymous 2007-01-22 2:57

303=297=295=me. 'Him' refers to you.

Name: LordRiordan 2007-01-22 2:58

I know that.
???

Name: Anonymous 2007-01-22 10:03 (sage)

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Name: Anonymous 2007-01-22 10:03 (sage)

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Name: Anonymous 2007-01-22 10:03 (sage)

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Name: LordRiordan 2007-01-22 11:32

THREAD CLOSED. Fag.

Name: Anonymous 2007-01-22 17:31

THREAD CLOSED.  NO U.

Name: Anonymous 2007-01-23 0:08 (sage)

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Name: Anonymous 2007-01-23 0:09 (sage)

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Name: Anonymous 2007-01-23 4:07

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Name: Anonymous 2007-01-23 7:42 (sage)

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