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ZERO is can be divide by ZERO!

Name: Anonymous 2006-11-05 22:51

OK, let's all just accept the truth:
0/0 = 1

Consider the following...
2/2 = 1
1/1 = 1
.246/.246 = 1
0.00000001/0.00000001 = 1
-4.72/-4.72 = 1
TACO/TACO = 1

Therefore, 0/0 = 1.
AMIRITE?

Name: Anonymous 2006-11-06 0:01

Get a life.

Name: Anonymous 2006-11-06 0:19

>>1
1 = 0/0 = (0 + 0)/0 = 0/0 + 0/0 = 1 + 1 = 2.

Name: Anonymous 2006-11-06 5:01

>>3
i lol'd

Name: Anonymous 2006-11-06 6:15

>>3
OP here. thank you sir! for a week i've been toying with the idea that maybe 0/0 could be an exception to the "can't divide by zero" rule. i've been trying to disprove it this way and that but couldn't get there myself (without slipping into the circular argument that one of the steps of my "proof" of 0/0=1 was faulty b/c "you can't divide by zero"). i figured if i posted this in an obnoxious enough way, someone would bite (instead of just saying GTFO: >>2 )
anyway, thanks... srsly

Name: Anonymous 2006-11-06 6:40

1=0/0 = (0 x 1)/(0 x 2) = (0/0)x(1/2) = 1 x 1/2 = 1/2

Name: Anonymous 2006-11-06 17:38

More reductio ad absurdum! why didn't I think of these... thanks.
- OP

Name: Anonymous 2006-11-06 18:09

0/0 is all real numbers fucktard

Name: Anonymous 2006-11-06 18:39

anything divided by 0 is infinity, which is a concept, not a number

Name: Anonymous 2006-11-06 21:39

>>9
mirrors

Name: Anonymous 2006-11-10 14:42

>>1
0/0 = 1 because a/a = 1
But 0/0 = ∞ because a/0 = ∞
And 0/0 = 0 because 0/a = 0

So 0/0 is a multiple paradox of number, meaning 0, 1 and ∞ at the same time

Name: Anonymous 2006-11-10 19:16

>>11
no...
0/0 = all reals EXCEPT for inf or 0.

Name: 4tran 2006-11-11 10:22

As it is written, 0/0 can mean anything.  In the context of limits, it might = a specific value.

limit((1-cos(x))/(sin(x)),(x->0)) = 0,
limit((1-cos(x))/(sin(x)^2),(x->0)) = 1/2
limit((1-cos(x))/(sin(x)^4),(x->0)) = +infinity

Name: Anonymous 2006-11-11 12:33

0 isn't an ordinary number

Name: Anonymous 2006-11-11 15:15

>>14
he's a complicated man, and no-one understands but his mother. ZERO!

Name: Anonymous 2006-11-12 2:46

Your problem comes from a fundamental misunderstanding of how division works. To devide a number x, you have to have a  solution to x = dq+r, where r < d. x is the number you are dividing, d is the "divisor" (the number you are diving by), q is the quotient (how many times does the divisor go into x?) and r is the remainder.

It's required for r < d, since that makes division a well-defined operation. Problem is, to divide 0, you end up with 0=q*0+0. r=d, thus, you cannot divide by 0.

Now, you can use limits to *estimate*, but as it's been pointed out, you can make 0/0 into any value you want with those.

Name: Anonymous 2006-11-12 13:26

anything*0=0
0/0=anything

Name: Anonymous 2006-11-14 11:50

if infinity is possible that would make zero unfathomable and therefore random.

>>17
speaks the truth

Name: Anonymous 2006-11-14 14:27

>>18
omng wow someone agreed with me!! I fele happy now ^__^!

Name: Anonymous 2006-11-14 14:53

>>19
Pity they were wrong.

Name: Anonymous 2006-11-14 18:51

LOL ALGEBRA, ADDITIVE IDENTITY ALWAYS LACKS A MULTIPLICATIVE INVERSE, ETC.

Name: Anonymous 2006-11-14 20:49

>>21

what about the zero ring? {0} lolz.

Name: Anonymous 2006-11-14 22:19

>>22
lol what about it?

Name: Anonymous 2006-11-15 6:08

>>21

Hey guy, your caps lock's on :p

oh wait, i'm sorry.

YOUR CAPS LOCK KEY'S ON, PLEASE CHECK IT.

Name: Anonymous 2006-11-15 15:52

>>23

0 is the additive and multiplicative identity. it's also the mupltiplicative and additive inverse.

Name: Anonymous 2006-11-15 23:05

>>25
TRIVIAL RING IS TRIVIAL

Name: Anonymous 2006-11-16 11:17

Dont be a fag. 0 / 0 doesn't exist. I win.

Name: Anonymous 2006-11-16 12:40

you can't divide in the trivial ring because if you could it would be a field and a field must have >= 2 elements. qed.

Name: Anonymous 2006-11-16 12:50

0/x = ?
0/6 = 0
0/5 = 0
0/4 = 0
0/3 = 0
0/2 = 0
0/1 = 0
0/x = 0


not like
1/x = ?
1/1 = 1
1/2 = .5
1/3 = .333
1/4 = .25
1/5 = .20
1/6 = .166

lim  1/x = 0
x-> infinite

Name: Anonymous 2006-11-16 13:55

>>28
Actually it would not have to be a field, just a division algebra. The point about having >=2 elements stands though, since that is true of division algebras as well.

Name: Anonymous 2006-11-17 6:36

>>29
0/0=anything

Name: Anonymous 2006-11-17 7:56

Division isn't defined for zero. Just as it isn't defined for racecar, love and herpes.

Name: Anonymous 2006-11-17 12:28

love/herpes = racecar

Name: Anonymous 2006-11-17 18:12

▄█▀ █■█ █ ▀█▀

Name: Anonymous 2006-11-18 12:38

0/0 = gay jesus

Name: Anonymous 2006-11-18 17:12

WAIT WAIT WAIT so we figured out zero can be 1 or 2 or infinite but can it be a negative number? I'm not thinking about it you do it for me!

Name: Anonymous 2006-11-18 19:04

0/0 = i/i
(0i^2)/0 = i^3/i    (multiply by i^2 on both sides)
0/0 = i^2 = -1

Name: Anonymous 2006-11-18 19:39

>>37
2 + 1 = 4
2 + 1 + 1 = 5  (add 1 to both sides)
2 + 2 = 5

If you begin with an incorrect statement, you can prove whatever you want.

Name: Anonymous 2006-11-18 20:22

>>38
0/0=anything
i/i≠anything

Name: Mr.Roboto 2006-11-19 13:04

Ok lets be real now people. We have come to the conclusion that 0/0=1 also that 0/a=0 and a/0=infinite. Therefor zero can equal 1,0,and infinite. This is a proven. Because everything divided by itself is one. Why should the trend stop at zero????

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