Rotational motion problems

Dear /sci/, I cannot for the life of me figure out how to do these two problems. If any kind person can provide a solution, please for the love of god make it as simple as possible since I'm retarded.

Love, Anonymous.

A smooth, thin rod, mass M=4.1 kg, and length L = 1.3 m, is spinning in a horizontal plane about a fixed vertical axis passing through one of its ends at an angular speed of w = 1.2 rad/s. A small ring of mass m = 0.010 kg, initially placed on the rod very close to the axis of rotation starts slowly sliding down the rod towards the other end of the rod. Calculate the speed of the ring when it reaches the other end of the rod

Anwser: 1.6

A homogeneous disk of radius R= 0.2m rotating at constant angular speed 21 rad/s about its central axis is carefully placed so that it simultaneously touches, both, a horizontal floor and a vertical wall. The coefficients of friction between the wall and the disk and the floor and the disk are the same mu = 0.05 . Calculate the angle, in degrees, the disk covers before stopping.

Answer: 1.6

>>2
Firstly for the second problem I just copy and plasted what was shown to me.. when I tried to solve it I couldn't figure out what force was pressing the disk against the wall but I thought that gravity was holding the disk on the ground. Perhaps since the disk was on the ground it would also roll toward the wall and thus keep it there. As for how to calculate that.. well thats why I'm here.

Secondly,
I see where you're going with the first problem.. but as I've said, I'm kinda retarded so a few things aren't making sense to me in your explaination. So a few things to clear up:

1) r(t) = distance = v * t  ...right?
2) I intergrate r'' = w^2*r (not sure where you got this from but I'll go with it) to get r' = (w^2 * r^2)/2 ; then r = (w^2 * r^3)/6
3) Given that r(t) = v*t, I set t = 0 to get that r' has  constant of zero, and r also has a constant of zero (probably totally wrong here...)
4) Find r(t) = 1.3 ...uh how?

That ends my train of thought. So.. I would much appreciate it if you could dumb down your explaination even more.