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Math Problem
1
Name:
Ein
2006-09-20 18:57
cant figure it out
^=exponent
2^2x - 33(2^x) + 32 = 0 solving for x
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Anonymous
2006-09-20 20:59
>>8
His points were valid: 5^x^2 (625) can be interpreted as (625)*5^(x^2) or (625)*(5^x)^2 or 5^(x^2 * 625) or 5^(x^(2*625)).
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