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A CHALLENGE

Name: Anonymous 2006-08-20 12:55

PROVE THAT EACH CLOSED SIMPLE PLANE CURVE HAS AT LEAST 4 POINTS WHERE THE CURVATURE VANISHES

Name: Anonymous 2006-08-20 13:56

>>2,3
CLOSED SIMPLE PLANE CURVE: BIJECTIVE MAP c: [a,b] -> R^2 SUCH THAT c[a] = c[b]. BIJECTIVITY IMPLIES IT NEVER INSECTS AND dc(s)/ds IS NEVER ZERO, WHERE WE TAKE dc PARAMERTICISED WITH ARC LENGTH s (HENCE ds IS THE ARC LENGTH DIFFERENTIAL)

THE CURVATURE OF A CLOSED SIMPLE PLANE CURVE c PARAMERTICISED TO UNIT VELOCITY IS |c''(t)| (I.E. IT'S ACCELERATION)

PROVE THAT ALL SUCH CURVES HAVE /AT LEAST/ 4 POINTS WHERE THE CURVATURE IS ZERO (IN ANY PARAMETRISATION)

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