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0.000~1=0

Name: Anonymous 2006-06-04 18:39

I am starting a new branch of mathematics called inverse decimal representation.

Name: Anonymous 2006-06-06 11:56

>>1
I don't think it'll hold since it's too easy to prove.

Given that 0.9999... = 1

0.9999... - 1 = 0.0000...1

Now, if 0.9999... really is equal to 1 as has been proven, then

1 - 1 = 0

Therefore,

0.0000...1 = 0 Exactly zero, by the way. Not close enough or almost 0, it is EXACTLY zero.

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