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e^(i(pi)) = -1
1
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Anonymous
2006-03-07 17:52
discuss
4
Name:
Anonymous
2006-03-07 19:28
>>3
Philosopher here.
e^(i(pi)) = cos(pi) + i * sin(pi) = -1 + I * 0 = -1
QED
I don't see how this is in anyway controversial...
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