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P = NP or P != NP ?

Name: Anonymous 2006-03-02 12:40

my opinion is that P = NP, [(X)^N] with N very high.

Name: Anonymous 2006-03-02 19:11

>>4
ops! You're true, I learned wrongly ;.;
thanks for the correction ^ ^ could you provide more info?
I'm such shit head

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