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x^(1/x) = a

Name: Anonymous 2006-01-06 21:55

x^(1/x) = a

find x in terms of a, K go!

Name: Anonymous 2006-01-25 13:25

>>40
You are even too stupid to realise the burden of proof is on you.

I didn't do maths in college, I have an A in A-level human biology, a B in chemistry and a B in English literature. I don't know the basic of maths, but this isn't because I'm stupid, but because I'm not omnipotent and haven't been taught maths past what I need to know for A-level chemistry. Now provide a proof.

Name: Anonymous 2006-01-25 13:26

>>40
I would also like to metnion you are inferior for not realising this.

Name: Anonymous 2006-01-25 17:13

>>41
>>42
Relax buddy. All that stress ain't good for yer heart.

Proof by contradiction:
blah blah blah
QED.

Since you don't know enough maths, then it's all the same to you anyway.

Name: Anonymous 2006-01-25 17:40

fuck, at least provide a link to it you fag

Name: Anonymous 2006-01-25 20:16

>>43
I see no proof.

Name: Anonymous 2006-01-26 1:39

Assume f(x)=x^(1/x). We are looking for it's inverse g(x)=f^-1(x) that can be expressed with a finite combination of the field operations (addition, multiplication, multiplicative inverse, addative inverse). We restrict ourselves to the rational numbers; since the rational numbers are closed under these operations it means that for each value of g(x), the argument of f(x) should be rational. However, taking g(2) we get 2=x^(1/x), for which no rational solution exists. We have a contradiction, which completes the proof.

Name: Anonymous 2006-01-27 2:00 (sage)

>>46
*clap clap clap* good sir, you have sucessfully ended this thread.

Name: Anonymous 2006-02-02 18:29

taking g(2) we get 2=x^(1/x)

how??

Name: Anonymous 2006-02-04 3:14 (sage)

>>48

The root of 2 is irrational (2^(1/2)). It's usually the first proof you learn when using contradiction and is accepted without having to state the proof over...unless of course you're a noob.

Name: Anonymous 2006-02-04 16:45

>>46
Wrong. Chaos theory implies otherwise. Let's take an ordinary equation.

Y = X^2

According to chaos theory you can find X in terms of Y. According to your theory this cannot be done.

X = Y^0.5

Now take a look at this equation, if you can't understand it you are an idiot and should gb2 high school as this thread is getting too complex for you.

sthliuashrituawrotguarwhliuahwzriuw\hr;liu\zwh\hul;wet=laweiGOTUIqwyoteiu\wyteojiWUHOTEIUq\3tkia\uh4wt

Name: Anonymous 2006-02-06 3:25

>>50
/r/ ban for stupid.

Name: Anonymous 2006-02-06 14:55

>>51
Seconded.

Name: Anonymous 2006-02-06 21:07

>>51
/r/ ban for refusing to provide proof

Name: Anonymous 2006-02-07 8:12

These hard math threads are troll heaven

Name: Anonymous 2006-02-07 14:50

>>54
The thing is they're not trolling, they just like to sit and jerk off at how smrt they are, when not everyone goes to college and does a course in Riemann geometry. It is sort of like taking 2 people, whisperring to one that sin(118^7)*65 in radians is 0.58407, then asking them the question and then going AHAHAHAH U R DUMB LOL when the one who wasn't told the answer says he can't do such an equation using mental arithmetic.

Name: Anonymous 2006-02-07 14:51

sin((118^7)*65)

Name: zeppy 2006-02-07 16:04 (sage)

z=xy

Name: Anonymous 2006-02-08 2:18

>>55 you must be either in grade-school or stuck in the 18th century, because mental arithmetic is pretty fucking useless at higher maths these days

Name: Anonymous 2006-02-08 4:11

>>58
It was an analogy you tard.

Name: Anonymous 2006-02-08 4:46

no it wasn't. you just couldn't think of a better example because you're fucking clueless.

if you think being a math nerd is somehow wrong then why are you even here? go back to your cave, turn on the tv and glorify all the beautiful celebrities or whatever it is you do

Name: Anonymous 2006-02-08 6:38

>>60
>>59 is not >>55, stfu.

Name: Anonymous 2006-02-09 22:45

x^(1/x) = 1/0

Name: Anonymous 2006-02-11 14:22

x ^ (1 / x) is:

if x == 0: ZeroDivisionError
if x == 1: 0
if x > 1: x
if x < 0: -x - 1

Name: Anonymous 2006-02-11 18:24

so when x > 1,
c = x?

or when x < 0,
c = -x -1?

Name: Anonymous 2006-02-11 20:11 (sage)

lol

Name: Anonymous 2006-02-12 11:26

>>64
What's this "c"? We haven't been introduced. I evaluated x ^ (1 / x) .

Name: Anonymous 2006-02-12 14:47

so when x > 1,
a = x?

or when x < 0,
a = -x -1?

Name: Anonymous 2006-02-12 15:13 (sage)

>>66
1^1=0?
troll harder

Name: Anonymous 2006-02-12 16:11

>>68
anonymous^anonymous = troll harder

Name: Anonymous 2006-02-15 9:44 (sage)

lol

Name: Anonymous 2006-02-21 21:22 (sage)

>>26
so fuck finity and a closed form, open the form and your fucking mind instead of limiting yourself because you cant understand it.
STRIVE

Name: Anonymous 2008-06-29 4:10

bump

Name: Anonymous 2008-07-01 17:12

>>46


but then again take e^x = a.

We can express x in terms of a using elementary functions only.

But it's not rational for any rational value other than 0.

You're proof shows that the inverse is not a finite polynomial with rational co-efficients, but I think that's all.

Name: Anonymous 2008-07-02 19:05

>>37
fuck analysis, fuck it straight in the ass

Name: Anonymous 2008-07-03 2:31

fuck it orthogonally

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