x^(1/x) = a
1
Name:
Anonymous
2006-01-06 21:55
x^(1/x) = a
find x in terms of a, K go!
2
Name:
Anonymous
2006-01-07 1:14
ln(x^(1/x)) = ln(a)
ln(x)/x = ln(a)
ln(x) = x*ln(a)
d[ln(x)]/dx = d[x*ln(a)]/dx
1/x = ln(a)
x = 1/ln(a)
i win amirite. OGC
3
Name:
Anonymous
2006-01-07 2:31
that transcendental equation has no analytic solution. nice try though!
4
Name:
Anonymous
2006-01-07 7:22
FUCK OFF AND DO YOUR OWN HOMEWORK NOOB
5
Name:
Anonymous
2006-01-07 10:29
(sage)
x^(1/x)=a
(x^(1/x))^x=a^x
x=a^x
x=a^(a^x)
x=a^(a^(a^x))
x=a^(a^(a^(a^x)))
infinite loop, OH SHI-
6
Name:
Anonymous
2006-01-07 12:39
>>2
Congrats and wow, I didn't think any of you retards would get it. You are all monotonous drones who don't truly understand the nature of the equation you utilise. Nice thinking.
Your reward is 1 free 4chan. Enjoy!
7
Name:
Anonymous
2006-01-07 12:56
actually you got it wrong
8
Name:
Anonymous
2006-01-07 12:56
bullshit! you can't just derive like that!
9
Name:
Anonymous
2006-01-07 13:24
(sage)
Yes you can, just fill it in:
(1/ln(a))^(1/(1/ln(a)))=a
(1/ln(a))^(ln(a))=a
ln(a)^(-ln(a))=a
Which is obviously true.
10
Name:
Anonymous
2006-01-07 14:51
taking a=1 instantly disproves the x=1/log(a) hypothesis.
11
Name:
Anonymous
2006-01-07 14:58
>>9
you're making me horny
12
Name:
Anonymous
2006-01-07 15:19
>>11
Cool. Wanna get together?
13
Name:
Anonymous
2006-01-07 15:33
>>4 wow, that's actually the correct answer... dumb fags
14
Name:
Anonymous
2006-01-07 16:09
>>6
I got it wrong, retard. a is a variable.
15
Name:
Anonymous
2006-01-07 20:20
fucking americans dont know math for shit no wonder your the fattest AND stupidest country in the world
16
Name:
Anonymous
2006-01-07 23:05
SOMEONE GET A PROFESSOR
17
Name:
Anonymous
2006-01-08 2:56
SOMEONE GET THIS THREAD A TROLL SWEEP
WOOP WOOP WOOP WOOP WOOP!
18
Name:
Anonymous
2006-01-08 16:13
pls answer pls
19
Name:
Anonymous
2006-01-09 3:12
there is no answer
20
Name:
Anonymous
2006-01-09 3:34
there should be an answer. it makes a graph doesn't it? rotate it 90degrees and you have x=..
21
Name:
Anonymous
2006-01-09 4:54
no. it's not solvable.
22
Name:
Anonymous
2006-01-09 9:35
-[LambertW(-ln(a))]/ln(a)
23
Name:
Anonymous
2006-01-09 11:12
elementary functions, even heard of them, you fruitcake? that's not a valid, closed-form solution.
24
Name:
Anonymous
2006-01-09 11:53
let "1" + "1" = "2".
now find "2" in terms of "1".
25
Name:
Anonymous
2006-01-09 12:46
>>23
Define an elementary function.
26
Name:
Anonymous
2006-01-09 13:55
>>25
polynomials, trigonometric functions, hyperbolic functions, logarithmic functions, exponential functions, n-th root functions, and their FINITE, CLOSED-FORM combinations.
for instance, erf(x) and zeta(x) do not qualify.
27
Name:
Anonymous
2006-01-09 17:57
The solution was already posted by
>>4 . Anyone posting after that is a fucking idiot.
28
Name:
Anonymous
2006-01-09 19:48
(sage)
>>27
Especially you, for not knowing that 4channers don't care.
29
Name:
Anonymous
2006-01-09 20:39
>>9
"obviously" lol, prove it fag.
30
Name:
Anonymous
2006-01-10 11:50
(sage)
>>28
YOU JUST GOT OWNED AHAHAHAHAHAHAHAHAH FGT
31
Name:
Anonymous
2006-01-10 16:31
needs more equations
32
Name:
Anonymous
2006-01-11 5:41
(sage)
>>31
give a parametric solution then
33
Name:
Anonymous
2006-01-11 15:15
34
Name:
Anonymous
2006-01-12 10:18
>>33
failt for learning math from wiki lol
35
Name:
Anonymous
2006-01-22 16:50
>>2
Actually that's false. You can't derive an equation like this it's meaningless.
>>3
He's right.
36
Name:
Anonymous
2006-01-23 20:55
make a proof
37
Name:
Anonymous
2006-01-24 5:05
(sage)
even if I do a proof you won't understand it because you haven't mastered ZF, FOL or elementary analysis.
38
Name:
Anonymous
2006-01-24 15:45
>>37
If you can't make a proof after spending 3 years studying maths in college or whatever it means you are stupid and inferior.
39
Name:
Anonymous
2006-01-25 8:50
This equation doesn't have a definite solution without YOF or RV
40
Name:
Anonymous
2006-01-25 12:34
>>38
I said that you're too dumb to understand it, not that I can't do it.
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