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Probability change

Name: Anonymous 2013-09-26 6:37

Suppose i have a set [A,B,C]
Probability of A =10% B=40% C=50%
If probability of C lowers to 25%, how the remainder value is distributed(proportionaly)?
I know it suppose to get like 15(+50%),60(+50%),25 but what if the set grows?
exmaple       5,77,3,15(-5) becomes 6.65,102,4,10
I'm looking for a formula for arbitrary sets of probability(not just 3).

Name: Anonymous 2013-09-26 6:58

>>2
>scale the set such that the sum of all elements =1
the problem, 1/sum(x) gives
 (1 / sum(X)) * X
5,77,3,15 -> 5,77,3,10 -> (100/95)~=*1.05-> 5.25,80.85,3.15,10
 (5 * (100 / 95)) + (77 * (100 / 95)) + (3 * (100 / 95)) + 10 = 99.4736842105
Which is 0.5% less than 100%

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