Pointers in C

Hey guys I'm having a little trouble with the following example

#include <stdio.h>
int main(void)
{
char s[] = "Melbourne City";
printf("%s\n", &s[2]);
return 0;
}

which prints "lbourne City" instead of the address of letter 'l'.
I do understand that the %s in the printf continues until a null terminator is hit, but not why &s[2] returns a character in the first place.
Thanks.

>>83
It's not about looks - the "Y U NO"-Guy depicted in that image is an embodiment of the frustration and anger with an individual or group neglecting to do something considered more or less essential in the given situation - in this case, neglecting to read da fuckin Standard.