How do you do this? (Python)

Consider a dice battle game called What-Are-the-Odds? It is a team battle game where team_ab plays against
team_cd and two players are on a team. Each player rolls a die and adds their roll value to their teammate’s
value. The first team_ab, will roll values represented by a and b. The second team_cd, will roll values
represented by c and d. Let the sum of the dice values for team_ab be represented by AB, and the sum of the dice
values for team_cd be represented by CD.
Rules of battle are as follows and apply to either team.
 Die values will be integers from 1 to 6, inclusive
 If only one of AB and CD are odd: The team with the odd number wins.
 If AB and CD are both odd: The largest odd number wins. If there is a tie, the individual rolls of a, b, c,
and d must be examined. The team with the largest odd number roll wins.
 If exactly one of AB or CD is an even number <= 6: The team with the even number loses.
 If AB and CD are both even and <=6: The team with AB or CD that is divisible by the largest odd
number wins.
 If AB and CD are both even and >6: The team with AB or CD that is divisible by the largest odd number
wins.
 A tie will occur in all situations in which a winner is not determined.
Write a python function, win_odds, that consumes 4 dice values, a, b, c, or d (integers 1-6), and produces
the winning team represented by a string (“AB”, “CD”, or “ABCD” when there is a tie). Some examples follow:


win_odds(2, 3, 6, 6) => “AB”
win_odds(2, 3, 5, 6) => “CD”
win_odds(2, 2, 1, 3) => “ABCD”
win_odds(1, 1, 1, 2) => “CD”
win_odds(3, 5, 5, 5) => “CD”
win_odds(2, 4, 2, 2) => “AB”
win_odds(1, 5, 1, 3) => “AB”
win_odds(6, 6, 4, 4) => “AB”

Bump.

what's the bfd? start with a variable set to the tie result ABCD. write a bunch of conditionals testing all those stupid rules that will change the result variable if need be. return the result variable

hurrrr

when will u python fags learn that javascript is superior?



function win_odds(a,b,c,d){var ab=a+b,cd=c+d,result='ABCD'; if(ab%2==1&&cd%2==0)result='AB'; if(ab%2==0&&cd%2==1)result='CD'; if(ab%2==1&&cd%2==1){if(ab==cd){var ab_odd=a%2==0?b:a, cd_odd=c%2==0?d:c; if(ab_odd!=cd_odd){result=ab_odd>cd_odd?'AB':'CD';}}else{result=ab>cd?'AB':'CD';}}else if(ab%2==0&&cd%2==0){if(ab<=6&&cd<=6){if(ab==6&&cd!=6)result='AB';else if(ab!=6&&cd==6)result='CD';}else if(ab>6&&cd>6){if(ab!=cd){if(ab==10||cd==10){result=ab==10?'AB':'CD';}else if(ab==12||cd==12){result=ab==12?'AB':'CD';}}}} return result;}

>>5
When will you learn how to properly indent your code?

>>5
should it return as soon as it gets a result?

>>6
indenting code... ever
python, forced indentation... no

>>7
what do you think faget? Ctrl-shift-J in chrome and copy and paste it and find out

>>8
>sacrificing readability for some bytes

>>7

it could if you gave that much of a shit. probably more of a style preference than anything. just assign the result and return it after all the spaghetti logic

>>10
implying i wrote it for you to read it
if you care that much do a jewgle search for "javascript beautifier"

def win_odds(a, b, c, d):
    ab = a + b
    cd = c + d
    result = 'ABCD'
    if (ab%2==1 & cd%2==0):
        result = 'AB'
    if (ab%2==0 & cd%2==1):
        result = 'CD'
    if (ab%2==1 & cd%2==1):
        if (ab==cd):
            ab_odd = a%2==0
            cd_odd = c%2==0
            if (ab_odd!=cd_odd):
                result = ab_odd > cd_odd
        else:
            result = ab>cd
    elif (ab%2==0 & cd%2==0):
        if(ab<=6 & cd<=6):
            if (ab==6 & cd!=6):
                result = 'AB'
            elif (ab!=6 & cd==6):
                result = 'CD'
        elif (ab>6 & cd>6):
            if(ab!=cd):
                if(ab==10|cd==10):
                    result = ab==10
                elif (ab==12|cd==12):
                    result = ab==12
    return result

>>13
lolno

>>14
Enlighten me

>>15
code tags

>>15
first of all, you turned some solid, thick, tight javascript into some ugly forced-indentation python. fuck that gay language

second, look at your return values for the lower spaghetti logic. when you assign "ab_odd > cd_odd" to the variable 'return', what the fuck are you getting back from your function? i don't know how python represents true/false values when you assign them to variables, but regardless of what it sends back it's not going to be 'AB' or 'CD' is it?

since python blows and doesn't have the ?: operator, you need to convert that too: http://stackoverflow.com/questions/2191890/conditional-operator-in-python

welp, i'm done doing your homework. you're welcome

win_odds(2, 4, 2, 2) => “AB”

undefined behaviour ^^

>>17

def win_odds(a, b, c, d):
    ab = a + b
    cd = c + d
    result = 'ABCD'
    if (ab%2==1 & cd%2==0):
        result = 'AB'
    if (ab%2==0 & cd%2==1):
        result = 'CD'
    if (ab%2==1 & cd%2==1):
        if (ab==cd):
            ab_odd = b if a%2==0 else a
            cd_odd = d if c%2==0 else c
            if (ab_odd!=cd_odd):
                result = 'AB' if ab_odd > cd_odd else 'CD'
        else:
            result = 'AB' if ab > cd else 'CD'
    elif (ab%2==0 & cd%2==0):
        if(ab<=6 & cd<=6):
            if (ab==6 & cd!=6):
                result = 'AB'
            elif (ab!=6 & cd==6):
                result = 'CD'
        elif (ab>6 & cd>6):
            if(ab!=cd):
                if(ab==10|cd==10):
                    result = 'AB' if ab==10 else 'CD'
                elif (ab==12|cd==12):
                    result = 'AB' if ab==12 else 'CD'
    return result

I know this language is ass, but give me a break.

>>18
refer to the rule "If AB and CD are both even and <=6: The team with AB or CD that is divisible by the largest odd
number wins."

it's AB = 6 and CD = 4.
 6 is divisible by 3 but 4 is only divisible by 1, so it's 'AB' and the result is correct.

>>1
good ol' pen and paper

>>20
*facepalm


def win_odds(a, b, c, d):
    ab = a + b
    cd = c + d
    result = 'ABCD'
    if (ab%2==1 and cd%2==0):
        result = 'AB'
    if (ab%2==0 and cd%2==1):
        result = 'CD'
    if (ab%2==1 and cd%2==1):
        if (ab==cd):
            ab_odd = b if a%2==0 else a
            cd_odd = d if c%2==0 else c
            if (ab_odd != cd_odd):
                result = 'AB' if ab_odd > cd_odd else 'CD'
        else:
            result = 'AB' if ab > cd else 'CD'
    elif (ab%2==0 and cd%2==0):
        if(ab<=6 and cd<=6):
            if (ab==6 & cd!=6):
                result = 'AB'
            elif (ab!=6 & cd==6):
                result = 'CD'
        elif (ab>6 and cd>6):
            if(ab!=cd):
                if(ab==10 or cd==10):
                    result = 'AB' if ab==10 else 'CD'
                elif (ab==12 or cd==12):
                    result = 'AB' if ab==12 else 'CD'
    return result

This is getting rather close...

Results
[code]
AB
CD
AB
CD
CD
ABCD
ABCD
AB
[code]

eh 4,4 - 3,3 is a draw though =)

I got it.