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Fucking C

Name: Anonymous 2012-11-03 14:43

Why it doesn't show me strings like "  a"?
Why is the while loop in the trim function bugged (if I input 2 chars the next input length can't be less than 2)?

#include <stdio.h>

#define MAX 1001

int getLine(char s[], int length){ // returns 1 or 0

    int i, qttWord = 0; //qttWord = counter of letters for s[]
    int c; // c = getchar()

    /*Reads the input and puts it into s[], then, verifies if the input is just \n,
    * if so, returns 0(i), if not, puts '\0' at the end of the string.
    */
    for (i = 0; i < length-1 && (c = getchar()) != EOF && c != '\n'; ++i){
            s[i] = c;
            ++qttWord;

    }
    if (i == 0){
        return 0;
    } else if (c == '\n'){
        ++i;
        s[i] = '\0';

    }
    /*Verifies if the string is just ' ' or '\t'
    * if so, returns 0
    */
    char flag = '\0';
    for (i = 0; i < qttWord && flag != '1'; ++i){
        if (s[i] == ' ' || s[i] == '\t'){
            flag = '0';
        } else{
            flag = '1';
        }
    }
    if (flag == '0')
        return 0;

    return qttWord;
}
void trim(char s[], int length){

    char s2[MAX];
    int i, qttWord = 0;

    /*while (s[length] != '\0'){
        ++length;
    }
    printf("length:%d\n", length);*/
    for (i = 0; i < length; ++i){
        if (i < length-1){
            if (s[i] == ' ' && s[i+1] != ' '){
                s2[i] = s[i];
                ++qttWord;
                printf("1:%d\n", s2[i]);// if true prints "1" and the character(' ')
            }
        }
        if (s[i] != ' '){
            s2[i] = s[i];
            ++qttWord;
            printf("0:%d\n", s2[i]);//if true prints "0" and the character
        }
    }
    s[0] = '\0';
    s2[qttWord] = '\0';

    for (i = 0; i < qttWord; ++i){
        s[i] = s2[i];
    }
    s2[0] = '\0';
}

int main(){
    char line[MAX];
    int lgh = 0;

    while ((lgh = getLine(line, MAX)) != 0){
        trim(line, lgh);
        printf("%s\n", line);
        line[0] = '\0';
        lgh = 0;
    }
    return 0;
}

Name: Anonymous 2012-11-05 1:57

>>86

A metric space is a pair (X, d), where X is a set, and d is a function defined as follows:

d: X * X -> R+

That is, d maps pairs of elements of X to the non negative real numbers. If a and b are elements of X, d(a,b) = r is interpreted as the distance between a and b.

d must satisfy the following properties:

\forall a \in X, d(a,a) = 0.  The distance from a point to itself is zero.

\forall a,b \in X, d(a,b) = d(b,a)  It doesn't matter from which end you measure the distance from.

And d must satisfy the triangle inequality:

\forall a,b,c \in X, d(a,b) + d(b,c) >= d(a,c)

A point is an element of X.

+\infty as seen in >>84 is nothing more than a symbol.

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