FizzBuzz

for i in range(110):
    pr = ""
    pr += "Fizz" * (i%3 == 0)
    pr += "Buzz" * (i%5 == 0)
    pr += "Bazz" * (i%7 == 0)
    print (pr if pr else i)

Beat this, faghets.

(function fizzbuzz(n, cases) {
      for (var i = 0; i < n; i++) {
        console.log(cases.reduce(function (prev, c) {
          return i % c[0] ? prev : (prev || '') + c[1];
        }, null) || i);
      }
    }(100, [[3, 'Fizz'], [5, 'Buzz'], [7, 'Bazz'], [11, 'Boo'], [13, 'Blip']]));

>hardcoding if statements
>2011