small string challenge

hi /prog/

I need to make a function that takes two strings, and removes all characters from the first string that are in the second string; we get marked on how efficient our code is. This is what I got so far, it's pretty shit and apparently theres a much better way to do it.


#include <iostream>
#include <string.h>

void rmFromString(std::string & toBeProcessed, const std::string & toBeIgnored)
{
        size_t found;
      std::string newString;

      found = toBeProcessed.find_first_not_of(toBeIgnored);

      while (found != std::string::npos)
      {
            newString += toBeProcessed[found];
            found = toBeProcessed.find_first_not_of(toBeIgnored, found + 1);
      }

    toBeProcessed = newString;

}

int main()
{
    std::string toBeProcessed = "she sells sea shells on the sea shore",
        toBeIgnored = "se";

    rmFromString(toBeProcessed, toBeIgnored);

    std::cout << toBeProcessed << std::endl;
}

anyone want to point me in the right direction?

>>21
s = ARGV[0].dup
ARGV[1].each_char { |c| s.delete!(c) }
puts s

I don't have an ALGOL compiler so I can't verify.