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multiple dispatch

Name: Anonymous 2012-01-21 4:10

Lisp:


[1]> (defclass B () ())
#<STANDARD-CLASS B>
[2]> (defclass C () ())
#<STANDARD-CLASS C>
[3]> (defgeneric f (x y))
#<STANDARD-GENERIC-FUNCTION F>
[4]> (defmethod f ((x B) (y B)) (print "BB"))
#<STANDARD-METHOD (#<STANDARD-CLASS B> #<STANDARD-CLASS B>)>
[5]> (defmethod f ((x B) (y C)) (print "BC"))
#<STANDARD-METHOD (#<STANDARD-CLASS B> #<STANDARD-CLASS C>)>
[6]> (defmethod f ((x C) (y B)) (print "CB"))
#<STANDARD-METHOD (#<STANDARD-CLASS C> #<STANDARD-CLASS B>)>
[7]> (defmethod f ((x C) (y C)) (print "CC"))
#<STANDARD-METHOD (#<STANDARD-CLASS C> #<STANDARD-CLASS C>)>
[8]> (f (make-instance 'B) (make-instance 'B))

"BB"
"BB"
[9]> (f (make-instance 'B) (make-instance 'C))

"BC"
"BC"
[10]> (f (make-instance 'C) (make-instance 'B))

"CB"
"CB"
[11]> (f (make-instance 'C) (make-instance 'C))

"CC"
"CC"
[12]>
Bye.


C++:


#include <iostream>

using namespace std;

struct A;
struct B;
struct C;

struct A {
  virtual ~A() {}

  virtual void f(A* y) = 0;

  virtual void f(B* y) = 0;
  virtual void f(C* y) = 0;

  virtual void g(B* y) = 0;
  virtual void g(C* y) = 0;
};

struct B : public A {
  void f(A* y);

  void f(B* y);
  void f(C* y);

  void g(B* y);
  void g(C* y);
};

struct C : public A {
  void f(A* y);

  void f(B* y);
  void f(C* y);

  void g(B* y);
  void g(C* y);
};

void B::f(A* y) { y->g(this); }

void B::f(B* y) { cout << "BB" << endl; }
void B::f(C* y) { cout << "BC" << endl; }

void B::g(B* y) { y->f(this); }
void B::g(C* y) { y->f(this); }


void C::f(A* y) { y->g(this); }

void C::f(B* y) { cout << "CB" << endl; }
void C::f(C* y) { cout << "CC" << endl; }

void C::g(B* y) { y->f(this); }
void C::g(C* y) { y->f(this); }

int main(int argc, char** argv) {
  A* b = new B();
  A* c = new C();
  b->f(b);
  b->f(c);
  c->f(b);
  c->f(c);
  delete b;
  delete c;
  return 0;


$ g++ gen.cpp
$ a.out
BB
BC
CB
CC

Name: Anonymous 2012-01-22 9:13

>>1
What happens if you forget to define one combination?

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