/prog/ - Code explanation

Name: Anonymous 2012-01-11 12:49

Can somebody explain why this code outputs what it does?

// tested with Core 2 Duo, Core 2 Quad and Xeon
// tested with gcc4.1.2 gcc4.4.3 and gcc4.6.1
// compile with: gcc -O0 -m32
#include <stdio.h>
#include <stdlib.h>
#include <signal.h>
#include <setjmp.h>

jmp_buf p;
void (*q)();

const char *data =
    "\x8b\x44\x24\x04\x8b\x5c\x24\x08"
    "\x8b\x00\x8b\x1b\x31\xc3\x31\xd8"
    "\x31\xc3\x8b\x4c\x24\x04\x89\x01"
    "\x8b\x4c\x24\x08\x89\x19\xc3\x90"
    "\x55\x89\xe5\x8b\x45\x04\xc9\xc3"
    "\x55\x90\x90\x89\xe5\x90\x90\x90"
    "\x8b\x45\x08\x89\x45\x04\xc9\xc3"
    "\x60\x09\x0e\x13\x14\x01\x0c\x0c"
    "\xc0\x07\x05\x0e\x14\x0f\x0f\x60"
    "\x00\x67\x6f\x74\x6f\x20\x63\x6f"
    "\x6e\x73\x69\x64\x65\x72\x65\x64"
    "\x20\x68\x61\x72\x6d\x66\x75\x6c"
    "\x6c\x00\x90\x90\x1c\x1b\x0a\x20";

int f(int x)
{
    static int b = 0; static int s = 0;
    int a = 0, t;
    if (!s) {
      a = b; b = x;
    } else {
      a = x; t = b;
      do {
      a ^= b;
      b = (a^b) & b;
      b <<= 1;
      } while (b);
      b = t;
    }
    s = (s+1) % 2;
    return a;
}

int g(int i, int *j)
{
    *j = i;
    i = (int) putchar;
    if (*j == (48 << 1))
      __asm volatile (
      "movl 8(%ebp),%eax;"
      "leave;"
      "ret"
      );
    return (int) puts;
}

void h(int i)
{
    int b;
    q = (void(*)()) g(i++[data],&b);
    for (f(b);*(data+i)!=b;++i,f(b))
      q(f(i[data])%0xff);
}

void sh(int s)
{
    if (s == 010)
      ((void(*)())g(s,&s))("F");
    longjmp(p,s);
}

int main(void)
{
    int base, addr = 0xffffffff, offs = 16;
    int a = 11, b = 32, i = 25;
    int s = 8, t = 1, u = 4;
    ((void(*)()) data)(&a,&b);
    ((void(*)()) data)(&b,&t);
    ((void(*)()) data)(&t,&s);
    addr ^= a;
   a ^= addr;
    addr ^= a;
    base = ((int(*)())data+addr)();
    if (a == -1)
      goto over;
    puts("A");

    base = (1<<3) | ((f(addr) + f(offs)) & ~0xff);
    h(base+addr+offs);
    exit(0);

over:
    signal(t,sh);signal(s,sh);signal(u,sh);

    if (!(s = setjmp(p))) {
      q = (void(*)()) g(0x30, &a);
      q(data + a + i);
      s = a / (b-1);
      puts("B");
    } else if (s == 0xb) {
      puts("C");
      ((int(*)(int)) data+addr+(offs/2))(base);
    } else {
      puts("D");
      *((int*) base+s) = 0xffffffff;
    }

    puts("E");
    return 1;
}

Code explanation

1 Name: Anonymous 2012-01-11 12:49

97 Name: Anonymous 2012-01-11 14:43

Name: Anonymous 2012-01-11 12:49

Name: Anonymous 2012-01-11 14:43