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fizz buzz

Name: Anonymous 2011-10-15 16:47

I have achieved my lifelong dream. Finally a fizz buzz program with 0 comparison operator.

#include <stdio.h>

#include <stdlib.h>



void main(int j){

  const char* s[] = {"%d\n", "fizz\n", "buzz\n", "fizzbuzz\n"};

  printf(s[3-!!(j%3)-2*!!(j%5)], j);

  (main+((exit-main)*(j/100)))((1-j/100)*j+1);

}

Name: Anonymous 2011-10-15 18:44

meh, could be more clean. move recursion to function "e"

#include <stdio.h>

#include <stdlib.h>

#include <stdint.h>

typedef uintptr_t p;

char *s[] = {"%d\n", "fizz\n", "buzz\n", "fizzbuzz\n"};

void e(int i) {

    

    printf(s[(!(i % 3)) | ((!(i % 5)) << 1)], i);

    (*((void(*)(int))((p)(e) + ((p)(exit) -

    (p)(e)) * (i / 100))))((1-i/100)*(i + 1));

}

int main() {

        e(1);

    return 0;

}

not sure if it is still warningless

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fizz buzz

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Name: Anonymous 2011-10-15 16:47

Name: Anonymous 2011-10-15 18:44