/prog/ - How to expert code

Name: Anonymous 2011-10-04 10:19





    // Split

    // Creates array of char* pointers to tokens, seperated by 'c'

    // a is array, al is number of elements

    // returns true on success, false on fail.

    // if success,  called should free a[0] (the string), and "a" itself (the arrya of pointers)

#include <stdio.h>

#include <string.h>

#include <stdlib.h>



int split(char *s, char c, char ***a, int *al) {

    char *ce = NULL; // current element

    char *ne = NULL; // next element

    char *p  = NULL;

    int  i   = 0;



    if(!s) {

        return -1;

    }



    // first pass: just count

    p = s;

    *al = 1;

    while(1) {

        p = strchr(p,c);

        if(!p) {

            break;

        }

        p++;

        (*al)++;

    }



    printf("count: %d\n",*al);



    // alloc our output

    *a = malloc(sizeof(char*)*(*al));



    // second pass actually splits

    s = strdup(s);

    ce = s;

    while(1) {

        ne = strchr(ce,c);

        if(ne) {

            *ne++ = 0;

        }

        (*a)[i] = ce;

        if(!ne) {

            break;

        }

        i++;

        ce = ne;

    }





    return 0;

}



int main(int argc, char **argv) {

    char**a = NULL;

    int n = 0;



    if(argc<3) {

        printf("args plz!\n");

        return 1;

    }



    split(argv[1],argv[2][0],&a,&n);



    int i;

    for(i=0;i<n;i++) {

        printf("a %02d: \"%s\"\n",i,a[i]);

    }



    return 0;

}

How to expert code

1 Name: Anonymous 2011-10-04 10:19

5 Name: Anonymous 2011-10-04 10:49

Name: Anonymous 2011-10-04 10:19

Name: Anonymous 2011-10-04 10:49