Memory allocation in C

I'm confused about how memory allocation works in C.
Consider the following code.

#include <stdio.h>
#include <stdlib.h>

int main(){
    int a[5];
    int *b;
    b = malloc(sizeof(char) * 5);
    printf("a = %lu b = %lu", sizeof(a), sizeof(b));
    free (b);
    return 0;
}

It returns sizeof(a) to be the actual size of the array a that I allocated. I thought C didn't keep any record of the size of arrays which was the reason why strings have to be null terminated so what's up with that?
On the other hand sizeof(b) returns just the size of the pointer not the size of the array. When I do free(b) how does it know how much memory to deallocate?

>>8
dumb jew
Jews are on average more intelligent than whites.
Is a dumb jew of average intelligence for whites?