>>29
Are you this fucking dumb. Okay, let's say I have the following loop....
int k = 0;
for (j = 1; j <= 20; j++) {
k = k + i;
}
The loop, in math terms, can be express as
f(n) = 20 * c
Or f of x is equal to some constant.
Now what happens when I change 20 to n?
int k = 0;
for (j = 1; j <= n; j++) {
k = k + i;
}
Where in is some unknown number that goes from 1 to whatever. Then I can express this as..
f(n) = n * c
So this means the function is now f of x equals to x. What is the upper bounds in this case you fucking faggot?