solve using unix tools
1
Name:
Anonymous
2011-05-09 8:08
input:
<table border="1">
<tr>
<td>row 1, cell 1</td>
<td>row 1, cell 2</td>
</tr>
<tr>
<td>row 2, cell 1</td>
<td>row 2, cell 2</td>
</tr>
</table>
output:
row\ 1,\ cell\ 1 row\ 1,\ cell\ 2
row\ 2,\ cell\ 1 row\ 2,\ cell\ 2
2
Name:
Anonymous
2011-05-09 8:40
3
Name:
Anonymous
2011-05-09 8:49
Backslashes necessary?
Also, Perl.
4
Name:
Anonymous
2011-05-09 10:32
>>3
No backslashes and perl makes it too easy.
5
Name:
Anonymous
2011-05-09 11:54
>>4
unix tools
Also how does not doing
s/ /\\&/g make it too easy?
6
Name:
Anonymous
2011-05-09 12:02
>>2
please, apoptose yourself
7
Name:
Anonymous
2011-05-09 12:10
print("row 1, cell 1 row 1, cell 2\n")
print("row 2, cell 1 row 2, cell 2")
am I doin it rite?
8
Name:
Anonymous
2011-05-09 13:09
I hope this will do
>>1 .
#include <iostream>
#include <string>
using namespace std;
int main() {
string input;
for( unsigned int i = 0; i < 10; i++ ) {
string tmp;
getline( cin, tmp );
if( cin.eof() ) return 0;
input += tmp + "\n";
}
string comparison = "<table border=\"1\">\n<tr>\n<td>row 1, cell 1</td>\n";
comparison +="<td>row 1, cell 2</td>\n</tr>\n<tr>\n<td>row 2, cell";
comparison +=" 1</td>\n<td>row 2, cell 2</td>\n</tr>\n</table>\n";
if( input.compare(comparison) == 0 ) {
cout << "row\\ 1,\\ cell\\ 1 row\\ 1,\\ cell\\ 2" << endl
<< "row\\ 2,\\ cell\\ 1 row\\ 2,\\ cell\\ 2" << endl;
}
return 0;
}
9
Name:
Anonymous
2013-09-01 23:09
In 1900, in the Paris conference of the International Congress of Mathematicians, David Hilbert challenged the mathematical community with his famous Hilbert's problems, a list of 23 unsolved fundamental questions which mathematicians should attack during the coming century. The first of these, a problem of set theory, was the continuum hypothesis introduced by Cantor in 1878, and in the course of its statement Hilbert mentioned also the need to prove the well-ordering theorem.
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