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Prime Number implementation

Name: Anonymous 2011-03-20 8:29


def factors(x):
    '''returns the factors for an integer'''
    facts=[]
    for i in range(x+1):
        if i==0:
            continue
        elif x%i==0:
            facts.append(i)
    return facts

def isprime(x):
    y=factors(x)
    if len(y)==2:
        return True
    else:
        return False

Name: Anonymous 2011-03-20 18:09

>>22
(define (factors x)
  (do ((i 1 (+ i 1))
       (r '() (if (zero? (remainder x i))
                  (cons x r) r)
)
)

    ((> i x) (reverse r)))
)


(define (prime? x)
  (or (= x 1)
      (= (length (factors x)) 2))
)

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