Someone with c++ knowledge please help

Im using visual c++ 2008 express edition from microsoft

Write a program that reads in 16 values from the keyboard and tests whether they form a magic square when put into a 4x4 array. You need to rest two features :

-does each of the numbers 1,2,...,16 occur in the user input
-When the numbers are put into a square, are the sums of the rows, columns, and diagonals equal to eachother?

a magic square is when the sum of the elements in each row, column and in the two diagonals have the same value.

Well, I'm still learning myself - but maybe to get you started:


using namespace std;
   
   int magic_square[4][4];
   int sum_rows[4] = {0, 0, 0, 0};
   int sum_cols[4] = {0, 0, 0, 0};
   int sum_diags[2] = {0, 0};
   
   cout << "Please enter 16 numbers:\n";
   
   // Collect user input
   for (int row = 0; row < 4; row++) {
      for (int col = 0; col < 4; col++) {
         while(!(cin >> magic_square[row][col])) {
            cin.clear();
            cin.ignore(10000, '\n');
            cout << "! Not a number, please try again:";        
         }
      }
   }
   
   // Display 4x4 table
   cout << "\nHere is the table:\n";
   for (int row = 0; row < 4; row++) {
      for (int col = 0; col < 4; col++) {
         cout << setw(8) << left << magic_square[row][col];
      }   
      cout << "\n";
   }

   // Sum of rows and columns 
   for (int i = 0; i < 4; i++) {
      for (int j = 0; j < 4; j++) {
         sum_rows[i] += magic_square[i][j];
         sum_cols[i] += magic_square[j][i];  
      } 
   }

   // Sum of diagonal from [0][0] to [3][3]
   for (int i = 0; i < 4; i++)
      sum_diags[0] += magic_square[i][i];
  
   // Sum of diagonal from [0][3] to [3][0]
   for (int i = 3, j = 0; i >= 0; i--, j++)
      sum_diags[1] += magic_square[i][j];
     
   // And... I'm too lazy to write something that compares all the values