[code][/code] tags.
public struct notacija : IComparable<notacija>
{
public int f;
public int g;
public int h;
public List<int> pot;
public int CompareTo(notacija other)
{
return f.CompareTo(other.f);
}
public notacija(int b, int c, int d)
{
f = b + c;
g = b;
h = c;
pot=new List<int>();
pot.Add(d);
}
public notacija(int b, int c)
{
f = b + c;
g = b;
h = c;
pot = new List<int>();
}
public void dodaj(int d, List<int> e)
{
pot=e;
pot.Add(d);
}
}
notacija temp = new notacija(0, 1, 2);
Notacija.Add(temp);
Notacija.Add(temp);
Notacija[0].pot.Add(1);
Notacija[1].pot.Add(2);
int stevec = 0;
string ss = "";
for (int b = 0; b < Notacija.Count; b++)
{
ss = "";
for (int a = 0; a < Notacija[b].pot.Count; a++)
{
ss += Notacija[b].pot[a] + " ";
}
MessageBox.Show(stevec + " " + ss);
}struct is a value type. However, this means that all fields are copied during an assignment (struct1 = struct2;), and when a field contains a reference, the reference is simply copied (a new object is not created!).
notacija X = new notacija(1, 2, 3);
notacija Y;
X = Y;
X.f = 2;
Y.f = 3;X.f and Y.f contain different values as they are fields of two different structs. However, X.pot and Y.pot point to the exact same reference, that is, the one created in the construct at X's initialization.
public notacija(notacija other) that initializes its own fields from other's. For value fields, you should simply do x.field=y.field;. For reference fields, you are going to have to create a new object of the same type, and copy over the values inside it manually.
MyClass X = new MyClass(1,3,4);
MyClass Y;
Y = new MyClass(X);
MyClass X = new MyClass(1,3,4);
MyClass Y;
Y = new MyClass(X);