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λ

Name: λ 2011-02-28 22:05

((λ (λ)
   (λ λ 0))
 (λ (λ n)
   (displayln (string-append "λ" (number->string n)))
   (λ λ (+ n 1))))

Name: Anonymous 2011-02-28 22:06

Needs more lambda

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