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Name: Anonymous 2011-02-09 11:54

Prove that this program terminates for all positive values of n.



def sequence(n):

  while n != 1:

    print n,

    if n%2 == 0:        # n is even

      n = n/2

    else:               # n is odd

      n = n*3+1

Name: Anonymous 2011-02-10 8:34

The function is never called so the program always terminates successfully as per the Python standard.

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