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C

Name: t work 2010-11-13 11:19

What's wrong with this shit? It's supposed to multiply every line seperatly for example we have the array
123
456
789

it's supposed to do this: 1*2*3=6 ; 4*5*6=120; 7*8*9=504;

#include <stdio.h>
#include <stdlib.h>

int main ()
{
    int mas1[2][3]={{1,2,3},{4,5,6},{7,8,9}};
    int mas[100];
    int i,j,m,n,k;
    j=0;
    i=0;
    m=2;
    n=3;

    for(k=0;k<=m;k++)
    {
                    mas[k]= mas1[i][j] * mas1[i][j+1] * mas1[i][j+2];
                    i++;
                    printf("%d",mas[k],",\t");
    }

    system("PAUSE");
    return 0;
}

Name: Anonymous 2010-11-13 11:24

Use code tags.

Name: Anonymous 2010-11-13 11:26

Try:

mas[k]= mas1[j][i] * mas1[j+1][i] * mas1[j+2][i];

Name: Anonymous 2010-11-13 11:27

system("PAUSE");

and you dare to say "what's wrong with this shit"?

Also, say [*] .comb for lines

Name: Anonymous 2010-11-13 11:28

Also:

int mas1[3][3]={{1,2,3},{4,5,6},{7,8,9}};

Not [2][3]

Name: mfw 2010-11-13 11:58

system("PAUSE");

q(〇_〇)p

Name: Anonymous 2010-11-13 11:59

hackish C style:

int a=0, i;
for(i=0;i<strlen(buf);i++) {
  if(buf[i] == 10) {
    printf("%d\n", a);
    a=0;
  } else if(buf[i] > 48) {
    a *= buf[i] -48;
  }
}
if(a > 0) printf("%d\n", a);

Name: Anonymous 2010-11-13 12:06

>>7
Learn to '0', and '\n', and '\r'.

Name: Anonymous 2010-11-13 12:25

>>4
I am in awe.

Name: Anonymous 2010-11-13 13:57

still not working

#include <stdio.h>
#include <stdlib.h>

int main ()
{
    int mas1[3][3]={{1,2,3},{4,5,6},{7,8,9}};
    int mas[100];
    int i,j,m,k;
    j=0;
    i=0;
    m=3;

    for(k=0;k<=m;k++)
    {
                    mas[k]= mas1[i][j] * mas1[i][j+1] * mas1[i][j+2];
                    i++;
                    printf("%d",mas[k],"\n");
    }


    return 0;
}

Name: Anonymous 2010-11-13 14:44

>>9
Chill out, it's just Perl 6

Name: Anonymous 2010-11-14 11:19

oh wait, it was all good, the printf was wrong
printf("%d\n",mas[k]);
and it's good

Name: Anonymous 2010-11-14 11:48


#include <stdio.h>

int main (int argc, char *argv[])
{
    auto int mas1[3][3] = {{1,2,3},{4,5,6},{7,8,9}};
    auto int mas[100] = {0};
    auto int i = 0, j = 0, m = 3;

    while (i < m) {
        mas[i] = mas1[i][j]*mas1[i][j+1]*mas1[i][j+2];
        printf("%i \n",mas[i]);
        ++i;
    }

    return 0;
}

:(

Name: Anonymous 2010-11-14 12:00


#include <stdio.h>
#include <stdlib.h>

int main (int argc, char *argv[])
{   
    int **mas1;
    int *mas;
    int *i,*j,*m;
   
    i    =    calloc(1,sizeof(int));
    j    =    calloc(1,sizeof(int));
    m    =    calloc(1,sizeof(int));
    m[0]=    3;
   
    mas    =    calloc(100,sizeof(int));
    mas1=    calloc(3,sizeof(int *));
    for(i[0]=0;i[0]<m[0];++i[0]){
        mas1[i[0]]        =    calloc(3,sizeof(int));
        mas1[i[0]][0]    =    j[0];
        mas1[i[0]][1]    =    j[0]+1;
        mas2[i[0]][2]    =    j[0]+2;
        j[0]=j[0]+3;
    }
    free(j);
   
    while (i[0] < m[0]) {
        mas[i[0]] = mas1[i[0]][0]*mas1[i[0]][1]*mas1[i[0]][2];
        printf("%i \n",mas[i[0]]);
        ++i;
    }

    for(i[0]=0;i[0]<m[0];++i[0])
        free(mas1[i[0]]);
    free(mas1);
    free(mas);
    free(i);
    free(m);
   
    return 0;
}

Name: Anonymous 2010-11-14 16:01

>>8
Posting a correct program would be helping him.

Name: Anonymous 2010-11-14 19:30

And we usually DON'T HELP HIM!!

Name: Anonymous 2010-11-15 3:05

>>15
>>16
what if it's a she?

Name: Anonymous 2010-11-15 3:45

>>17
There are no women on the internet.

Name: Anonymous 2010-11-15 10:55

>>17
I know a few women. They have better sense than to visit /prog/. It's easy to extrapolate that none would come here, or at least if they did, they would ask better questions.

Name: Anonymous 2010-11-15 16:50

>>19
I know a few women.
Megaaaaaaaaan....

Name: Anonymous 2010-11-16 0:41

I'm going to rape you in the butthole if you ever use system("PAUSE") again.

Name: Anonymous 2010-11-16 3:06

>>21
whyyyyyyyyyyyyyyyyyyy

Name: Anonymous 2010-11-16 6:07

>>21 ahh... the romance...

Name: Anonymous 2010-11-16 6:10

>>21
the timeless art of seduction

Name: Anonymous 2010-11-17 16:22

nerds LOL

Name: Anonymous 2010-11-17 16:30

>>25
Fuck off, ``faggot''.

Name: Anonymous 2010-11-17 16:44

>>21
THE PLEASURE OF BEING CUMMED INSIDE

Name: Anonymous 2010-12-25 7:40

Name: Anonymous 2013-09-09 3:28

>>1
USE THE [code] TAGS!!!
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