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BINARY

Name: Anonymous 2010-11-10 18:20

So is this an efficient way to print out a 32bit little-endian integer in binary?



void printBinary(int number)

{

    char temp[33];

    char* p = &temp[32];

    int mask = 1;

    *p = 0;

    for (int i = 0; i < 32; ++i)

    {

        --p;

        *p = (number & mask) + 48;

        mask <<= 1;

    }

    puts(temp);

}

Name: Anonymous 2010-11-10 19:18



#include <stdio.h>

#include <stdint.h>

 

void print_binary(uint32_t n)

{

    uint32_t mask = ~((uint32_t)~0 >> 1);

    do

        printf(n & mask ? "1" : "0");

    while (mask >>= 1);

}

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