Name: Anonymous 2010-10-23 19:15
<define name="f">
<lambda args="x">
<multiply>
<variable name="x" />
<funccall func="f">
<subtract>
<variable name="x" />
<int value="1" />
</substract>
</funccall>
</multiply>
</lambda>
</define>IT WILL BRING PROGRAMMING TO A WHOLE NEW LEVEL!