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On virtual machines and expected behaviour

Name: Anonymous 2010-05-17 19:44

Ever tried running this on your ENTERPRISE VIRTUAL MACHINE?

 Integer a = 1000;

 Integer b = 1000;

 System.out.println("a == b (1000 == 1000): " + (a == b));



 Integer aa = 100;

 Integer bb = 100;

 System.out.println("aa == bb (100 == 100): " + (aa == bb));

Guess what's the output, run it and report back.

Name: Anonymous 2010-05-17 22:45

>>26
HIBT?
If p is a value of type int, then boxing conversion converts p into a reference r of class and type Integer, such that r.intValue() == p
In general, using == on two integers produces undefined behavior. What is so hard to understand about this?

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On virtual machines and expected behaviour

1 Name: Anonymous 2010-05-17 19:44

27 Name: Anonymous 2010-05-17 22:45

Name: Anonymous 2010-05-17 19:44

Name: Anonymous 2010-05-17 22:45