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Name: Anonymous 2010-04-10 17:56

If I write the code int i, j; can I assume that (&i + 1) == &j?

Only sometimes. It's not portable, because in EBCDIC, i and j are not adjacent.

Name: Anonymous 2010-04-10 18:12

>>1
because in EBCDIC, i and j are not adjacent.
Haha, very funny man. Why don't you just go eat a dish of your favourite food?

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