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Haskell point-free

Name: Anonymous 2009-12-25 17:12

I have this:



ops :: [[Char] -> [Char]]

...

fun :: [Char] -> [[Char]]

fun str = zipWith ($) ops $ words str

How do I write fun in a point-free style? Dropping the argument gives me type errors.

Name: Anonymous 2010-01-09 15:01

>>47
elem :: (Eq a) => a -> [a] -> Bool

How is that going to match a1 -> r?

Name: HMA FAN 2010-01-09 15:06

>>47
I chortl'd.
elem :: Eq a => a -> [a] -> Bool
Protip: liftM2

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