Sepplesfags, help!


template <class T>
class A
{
public:
    typedef T Foo;
};

template <class T>
class B
{
    A<T>::Foo foo;
};

int main()
{
    B<int> b;
    return 0;
}


test.cpp:11: error: type ‘A<T>’ is not derived from type ‘B<T>’
test.cpp:11: error: expected ‘;’ before ‘foo’


What the FUCK?

>>11
Inheritance does not mean access.  When you derived B from A you inherited the Foo function, so every B has its own Foo to call.  This does not mean that nonlocal A's have to give access to their protected methods in B methods now.

Whereas your other example has nothing to do with this at all. Foo is used within one of the other class methods. Nothing wrong with that.