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C arrays

Name: Anonymous 2008-11-15 10:18

is there a way to do this all in one function instead of splitting it into two?
#include <stdlib.h>

void stuff_with_a(char a[20000000][20]){
 for(int i = 0; i < 20000000; ++i){
  for(int j = 0; j < 20; ++j)
   a[i][j] = 0;
 }
}

int main(){
 char *a = malloc(20000000*20);
 stuff_with_a(a);
 sleep(60);
 return 0;
}

Name: Anonymous 2008-11-17 17:35

>>35
Huh, I was under the impression that sizeof required parenthesis.


#include <stddef.h>

int main()
{
    size_t a = sizeof int;
    return 0;
}



test.c: In function ‘main’:
test.c:5: error: expected expression before ‘int’


Yep, I think sizeof needs those parens.

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