Name: Anonymous 2008-08-03 15:59
Sup guise,lets be logic:
Also,NO INDENTATION OF CODE
factorial=lambda x:((x==1 and 1) or x*factorial(x-1))
fizzbuzz=lambda i:[str(((not x%3) and x%5 and 'fizz') or ((not x%5) and x%3 and 'buzz') or ( ((not x%5) and (not x%3)) and 'fizzbuzz') or x) for x in range(1,i+1)]Also,NO INDENTATION OF CODE