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God damn Haskell

Name: Anonymous 2008-07-13 8:35


import IO

main :: IO ()
main = do
        putStr "Name: "
        n <- getLine
        putStrLn n


/prog/, why doesn't this code work? I understand laziness, so "n" won't be evaluated until it's needed in "putStrLn", but why does "n" get evaluated, then "putStr" and "putStrLn" get evaulated?

tl;dr How the hell do you prompt for information in Haskell?

Name: Anonymous 2008-07-13 10:15

>>11
Are you fucking retarded you fucking piece of shit, who the fucking flying fuck doesn't know about buffering?
Yes, I said n00bs because I'm superior. So what? I can't have friends because I'm superior to OP? Your logic is broken.

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